Speakers and ohms?

[daydreamdelay]

I recently got a Traynor YBA-1 and would like to load one of my empty cabs.. I have no idea what speakers/ohms to get, there's a local ad for a pair of Celestion G12T-75's that are 16 ohms for $75

I'm wondering first of all if these would work with the head I have, based on what's listed on a Traynor site it doesn't seem so but I'm wondering if it can be wired to work?  and secondly are these good speakers for the amp I have?


One main speaker output, impedance is not indicated (runs fine using a cab of eight ohms, also often operated with four ohm loads), one "extension" speaker output also without indicated impedance. A YBA-1 has a nominal 8 ohm output, and the two speaker jacks are wired in parallel.

[mynameisjonas]

my marshall cab is loaded with G12T-75s and i think they sound great. you should be able to use them with your traynor... i´m not 100% sure, but i think two 16 ohm speakers can be wired so the load is 8 ohms :-\

i don´t know if the speakers in my cab are 16 ohms, but the different switching options are:
4 ohms (4 speakers)
16 ohms (4 speakers)
8 ohms (2 speakers)

[Jay]

If everything I remember is correct, it would be okay to use a 16Ω load hooked to an 8Ω output without fear of damaging the output transformer or eating up your power tubes.  The risk comes when using a load that is too low like 4Ω on a 8Ω output.  I've heard of people mismatching on purpose because they like the sound of a 16Ω cabinet on a 4 or 8Ω load.  Don't take this as gospel though, I'm just going on things I seem to have heard over many years of reading about this stuff.  I have no actual hard data on this for you.

[luau]

Here's the math:

Wiring them in series increases total  resistance and wiring them in parallel reduces total resistance.

Total resistance of resistors in series is just a sum of each individual resistor. Total R = R1 + R2 + R3 + Rn-1 + Rn
If your amp wants 8 ohms  then 2 4 ohm speakers in series would make it happy. 4 + 4 = 8.

Total resistance of resistors in parallel is less simple. Total R = 1 / ((1 / R1) + (1 / R2) + (1 / R3) + (1 / Rn-1) + (1 / Rn)).
If you amp wants 8 ohms then 2 16 ohm speakers in parallel would make it happy. 1 / (1/16 + 1/16) = 1/(.0625 + 0.0625) = 1/.125 = 8.

My physics instructor would be so proud.

[pullover]

two  16Ω speakers can be wired to be 8Ω. Just wire them in parallel.



http://www.bcae1.com/spkrmlti.htm

[daydreamdelay]

cool.. thanks for the info 

this is for a 4x12 cab.. what will I have to do when I get the other two speakers?  will another set of 16 ohm speakers work or will I need to get something else?

also this may be kind of a stupid question but is there a specific way I should load these two.. top, bottom, side, diagonally 

[pullover]

If you are going to use a 4x12 cab I would suggest getting four 8Ω speakers. You would wire two pairs of speakers in series, then wire those pair in parallel. Like in Figure 3a. Or you could just use four 32 ohm speakers in Parallel.  I wouldn't suggest mixing different impedance speakers.

[daydreamdelay]

ahh.. guess I should pass on these then

thanks for the advice and diagrams